SATHEE: Permutations And Combinations Question 345

Permutations And Combinations Question 345

Question: The number of ways in which a mixed doubles game in tennis can be arranged form 5 married couples, if no husband and wife play in the same game, is

Options:

A) 46

B) 54

C) 60

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

[c] Let the sides of the game be A and B given 5 married couples, i.e, 5 husband and 5 wives. Now, 2 husbands for two sides A and B can be selected out of $ 5{{=}^{5}}C_2=10 $ ways. After choosing the two husbands their wives are to be excluded (since no husband and wife play in the same game). So we have to choose 2 wives out of remaining 5 - 2 = 3 wives i.e., $ ^{3}C_2=3 $ ways. Again two wives can interchange their sides A and B in 2! =2 ways. By the principle of multiplication, the required number of ways $ =10\times 3\times 2=60 $

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Permutations And Combinations Question 345

Question: The number of ways in which a mixed doubles game in tennis can be arranged form 5 married couples, if no husband and wife play in the same game, is

Options:

Answer:

Solution:

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