SATHEE: Permutations And Combinations Question 35

Permutations And Combinations Question 35

Question: There are 10 persons named $ A,\ B,…….J $ . We have the capacity to accommodate only 5. In how many ways can we arrange them in a line if $ A $ is must and $ G $ and $ H $ must not be included in the team of 5

Options:

A) $ ^{8}P_5 $

B) $ ^{7}P_5 $

C) $ ^{7}C_3(4\ !) $

D) $ ^{7}C_3(5\ !) $

Show Answer

Answer:

Correct Answer: D

Solution:

Out of 10 persons, $ A $ is in and $ G $ and $ H $ are out of the team, so we have to select 4 more from 7 remaining. This can be done in $ ^{7}C_4 $ ways. These 5 persons can be arranged in a line in $ 5\ ! $ ways. Hence the number of possible arrangements is $ ^{7}C_4.\ 5\ !\ {{=}^{7}}C_3.(5\ !) $ .

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Permutations And Combinations Question 35

Question: There are 10 persons named $ A,\ B,…….J $ . We have the capacity to accommodate only 5. In how many ways can we arrange them in a line if $ A $ is must and $ G $ and $ H $ must not be included in the team of 5

Options:

Answer:

Solution:

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