SATHEE: Permutations And Combinations Question 372

Permutations And Combinations Question 372

Question: How many different nine digit numbers can be formed form the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

Options:

A) 16

B) 36

C) 60

D) 180

Show Answer

Answer:

Correct Answer: C

Solution:

[c] X-X-X-X-X. The four digits 3, 3, 5, 5, can be arranged at (-) places in $ \frac{4!}{2!2!}=6 $ ways. The five digits 2, 2, 8, 8, 8, can be arranges at (x) place in $ \frac{5!}{2!3!} $ ways = 10 ways Total no. of arrangements $ =6\times 10=60 $ ways

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Permutations And Combinations Question 372

Question: How many different nine digit numbers can be formed form the number 223355888 by rearranging its digits so that the odd digits occupy even positions?

Options:

Answer:

Solution:

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