Permutations And Combinations Question 377
Question: The sum of all the numbers of four different digits that can be made by using the digits 0, 1, 2 and 3.
Options:
A) 64322
B) 48522
C) 38664
D) 1000
Correct Answer: C $ \therefore $ The sum of the digits in the unit place $ =6\times 0+4\times 1+4\times 2+4\times 3=24 $ Similarly for the tens and the hundreds places. The number of numbers with 1 or 2 or 3 in the thousands place =3! $ \therefore $ The required sum $ =36\times 100+24\times 100+24\times 10+24=38664 $
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Answer:
Solution:
$ \therefore $ The sum of the digits in the thousands place $ =6\times 1+6\times 2+6\times 3=36 $
BETA
