Permutations And Combinations Question 50
Question: There are three girls in a class of 10 students. The number of different ways in which they can be seated in a row such that no two of the three girls are together is
Options:
A) $ 7\ !\ {{\times }^{6}}P_3 $
B) $ 7\ !\ {{\times }^{8}}P_3 $
C) $ 7\ !\ \times 3\ ! $
D) $ \frac{10\ !}{3\ !\ 7\ !} $
Show Answer
Answer:
Correct Answer: B
Solution:
- Seven boys can be seated in a row in $ 7\ ! $ ways. Hence the total no. of arrangement such that no two girls seated together $ =7\ !\ {{\times }^{8}}P_3 $ .
BETA
