A) $ n>2 $
B) $ n\in N $
C) $ n>3 $
D) None of these
Correct Answer: A
Show Answer
Answer:
Solution:
$ \therefore P(k+1)=(k+1)!=(k+1)k!>(k+1){2^{k-1}} $ $ >2^{k},(ask+1>2) $
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