A) For $ n\ge 6 $
B) For $ n\ge 7 $
C) For $ n\ge 3 $
D) For all n.
Correct Answer: B
Show Answer
Answer:
Solution:
$ \Rightarrow P(k+1):{3^{k+1}} $ $ ={{3.3}^{k}}<3.k!<(k+1)!(\because k+1>3) $
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