Probability Question 10
Question: A can hit a target 4 times in 5 shots;
B can hit a target 3 times in 4 shots; C can hit a target 2 times in 3 shots; All the three a shot each. What is the probability that two shots are at least hit?
Options:
A) 1/6
B) 3/5
C) 5/6
D) 1/3
Show Answer
Answer:
Correct Answer: C
Solution:
Probability of no one hitting the target $ =\frac{1}{5\times 4\times 3}=\frac{1}{60} $
Probability of one hitting the target $ =\frac{4+3+2}{60}=\frac{9}{60} $
$ \therefore $ Probability of maximum one hit $ =\frac{1}{60}+\frac{9}{60}=\frac{10}{60}=\frac{1}{6} $
Probability that two shots are hit at least is the required probability $ =1-\frac{1}{6}=\frac{5}{6} $
BETA
