Probability Question 11
Question: It has been found that if A and B play a game 12 times. A wins 6 times, B wins 4 times and they draw twice. A and B take part in a series of 3 games. The probability that they with alternately, is:
Options:
A) $ 5/12 $
B) $ 5/36 $
C) $ 19/27 $
D) $ 5/27 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ P(A)=\frac{6}{12}=\frac{1}{2},P(B)=\frac{4}{12}=\frac{1}{3} $
Req. probability $ =\frac{1}{2}.\frac{1}{3}.\frac{1}{2}+\frac{1}{3}.\frac{1}{2}.\frac{1}{3}=\frac{1}{12}+\frac{1}{18}=\frac{5}{36} $
BETA
