Probability Question 111
Question: A pack of cards contains 4 aces, 4 kings, 4 queens and 4 jacks. Two cards are drawn at random. The probability that at least one of these is an ace, is
[MNR 1991]
Options:
A) $ \frac{9}{20} $
B) $ \frac{3}{16} $
C) $ \frac{1}{6} $
D) $ \frac{1}{9} $
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Answer:
Correct Answer: A
Solution:
Required probability is $ 1-P $ (No Ace) $ =1-\frac{{}^{12}C_2}{{}^{16}C_2}=1-\frac{12.11}{16.15}=\frac{9}{20}. $
BETA
