SATHEE: Probability Question 112

Probability Question 112

Question: Given two mutually exclusive events A and B such that $ P(A)=0.45 $ and $ P(B)=0.35, $ then P (A or B) =

[AI CBSE 1979]

Options:

A) 0.1

B) 0.25

C) 0.15

D) 0.8

Show Answer

Answer:

Correct Answer: D

Solution:

$ P(A\cup B)=P(A)+P(B) $ = $ 0.45+0.35=0.8. $

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Probability Question 112

Question: Given two mutually exclusive events A and B such that $ P(A)=0.45 $ and $ P(B)=0.35, $ then P (A or B) =

Options:

Answer:

Solution:

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