Probability Question 120
Question: 5 persons A, B, C, D and E are in queue of a shop. The probability that A and E always together, is
Options:
A) $ \frac{1}{4} $
B) $ \frac{2}{3} $
C) $ \frac{2}{5} $
D) $ \frac{3}{5} $
Show Answer
Answer:
Correct Answer: C
Solution:
Total number of ways $ =5! $
Favourable number of ways $ 2.4! $
Hence required probability $ =\frac{2.4!}{5!}=\frac{2}{5} $ .
BETA
