Probability Question 122
Question: From eighty cards numbered 1 to 80, two cards are selected randomly. The probability that both the cards have the numbers divisible by 4 is given by
[Pb. CET 2000]
Options:
A) $ \frac{21}{316} $
B) $ \frac{19}{316} $
C) $ \frac{1}{4} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Total number of ways $ ={{}^{80}}C_2 $ and favorable ways $ {{=}^{20}}C_2 $ \ Required probability $ P=\frac{^{20}{C_{_2}}}{^{80}C_2}=\frac{19}{316} $ .
BETA
