Probability Question 128
Question: Twelve tickets are numbered 1 to 12. One ticket is drawn at random, then the probability of the number to be divisible by 2 or 3, is
Options:
A) $ \frac{2}{3} $
B) $ \frac{7}{12} $
C) $ \frac{5}{6} $
D) $ \frac{3}{4} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ P(2\cup 3)=P(2)+P(3)-P(2\cap 3) $
$ =\frac{6}{12}+\frac{4}{12}-\frac{2}{12}=\frac{2}{3}. $
BETA
