Probability Question 158

If A and B are two events such that $ P(A)=\frac{1}{3} $ , $ P(B)=\frac{1}{4} $ and $ P(A\cap B)=\frac{1}{5}, $ then $ P( \bar{B} \mid \bar{A} )= $

Options:

A) $ \frac{37}{40} $

B) $ \frac{37}{45} $

C) $ \frac{23}{40} $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

$ P( \frac{{\bar{B}}}{{\bar{A}}} )=\frac{1-P(A\cup B)}{P(\bar{A})}=\frac{1-\frac{23}{60}}{1-\frac{1}{3}}=\frac{37}{60}\times \frac{3}{2}=\frac{111}{60}. $



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