Probability Question 16
Question: The records of a hospital show that 10% of the cases of a certain disease are fatal. If 6 patients are suffering from the disease, then the probability that only three will die is
[MP PET 1998]
Options:
A) $ 1458\times {10^{-5}} $
B) $ 1458\times {10^{-6}} $
C) $ 41\times {10^{-6}} $
D) $ 8748\times {10^{-5}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Probability of disease is fatal = $ p=10% $
$ p=\frac{10}{100}=\frac{1}{10},q=\frac{9}{10} $
Number of patients = 6,
Number of die cases = 3
$ \therefore $ Probability that 3 will die $ ={}^{6}C_3{{( \frac{1}{10} )}^{3}}{{( \frac{9}{10} )}^{3}}=1458\times {10^{-5}} $ .
BETA
