SATHEE: Probability Question 165

Probability Question 165

Question: If $ 4P(A)=6P(B)=10P(A\cap B)=1, $ then $ P( \frac{B}{A} )= $

[MP PET 2003]

Options:

A) $ \frac{2}{5} $

B) $ \frac{3}{5} $

C) $ \frac{7}{10} $

D) $ \frac{19}{60} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ P( \frac{B}{A} )=\frac{P(A\cap B)}{P(A)}=\frac{(1/10)}{(1/4)}=\frac{2}{5}. $

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Probability Question 165

Question: If $ 4P(A)=6P(B)=10P(A\cap B)=1, $ then $ P( \frac{B}{A} )= $

Options:

Answer:

Solution:

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