Probability Question 175
Question: A biased die is tossed and the respective probabilities for various faces to turn up are given below
| Face : | 1 | 2 | 3 | 4 | 5 | 6 |
| Probability : | 0.1 | 0.24 | 0.19 | 0.18 | 0.15 | 0.14 |
If an even face has turned up, then the probability that it is face 2 or face 4, is
[MNR 1992]
Options:
A) 0.25
B) 0.42
C) 0.75
D) 0.9
Show Answer
Answer:
Correct Answer: C
Solution:
Let $ A $ be the event that even face turns up and $ B $ be the event that it is 2 or 4. Then $ P(A)=P(2)+P(4)+P(6)=0.24+0.18+0.14=0.56 $
$ P(B)=P(2)+P(4)=0.24+0.18=0.42 $ So, $ P(B/A)=\frac{P(B\cap A)}{P(A)}=\frac{P(B)}{P(A)}=\frac{0.42}{0.56}=0.75 $ .
BETA
