Probability Question 180
Question: For a biased die the probabilities for different faces to turn up are given below
| Face : 1 | 2 | 3 | 4 | 5 | 6 | |
| Probability : | 0.1 | 0.32 | 0.21 | 0.15 | 0.05 | 0.17 |
The die is tossed and you are told that either face 1 or 2 has turned up. Then the probability that it is face 1, is
[IIT 1981]
Options:
A) $ \frac{5}{21} $
B) $ \frac{5}{22} $
C) $ \frac{4}{21} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Required probability $ =\frac{0.1}{0.1+0.32}=\frac{0.1}{0.42}=\frac{5}{21}. $
BETA
