Probability Question 184
Question: The binomial distribution for which mean = 6 and variance = 2, is
Options:
A) $ {{( \frac{2}{3}+\frac{1}{3} )}^{6}} $
B) $ {{( \frac{2}{3}+\frac{1}{3} )}^{9}} $
C) $ {{( \frac{1}{3}+\frac{2}{3} )}^{6}} $
D) $ {{( \frac{1}{3}+\frac{2}{3} )}^{9}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ np=6 $
$ npq=2\Rightarrow q=\frac{1}{3},p=\frac{2}{3} $ and $ n=9. $
Hence the binomial distribution is $ {{( \frac{1}{3}+\frac{2}{3} )}^{9}}. $
BETA
