Probability Question 193
Question: One ticket is selected at random from 100 tickets numbered 00, 01, 02, …… 98, 99. If X and Y denote the sum and the product of the digits on the tickets, then $ P(X=9/Y=0) $ equals
Options:
A) $ \frac{1}{19} $
B) $ \frac{2}{19} $
C) $ \frac{3}{19} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Event $ (Y=0) $ is $ {00,01,09,10,20,……….90} $
Also $ (X=9)\cap (Y=0)=09,90, $ we have $ P(Y=0)=\frac{19}{100} $ and $ P(X=9)\cap (Y=0)=\frac{2}{100} $
Hence required probability $ =P{ (X=9)/(Y=0) }=\frac{{ P(X=9)\cap (Y=0) }}{P(Y=0)}=\frac{2}{19} $ .
BETA
