Probability Question 234
Question: Suppose that A, B, C are events such that $ P(A)=P(B)=P(C)=\frac{1}{4},P(AB)=P(CB)=0,P(AC)=\frac{1}{8}, $ then $ P(A+B)= $
[MP PET 1992]
Options:
A) 0.125
B) 0.25
C) 0.375
D) 0.5
Show Answer
Answer:
Correct Answer: D
Solution:
$ P(A+B)=P(A)+P(B)-P(AB) $
$ =\frac{1}{4}+\frac{1}{4}-0=\frac{1}{2}. $
BETA
