Probability Question 259
Question: If A and B an two events such that $ P(A\cup B)=\frac{5}{6} $ , $ P(A\cap B)=\frac{1}{3} $ and $ P(\bar{B})=\frac{1}{3}, $ then $ P(A)= $
Options:
A) $ \frac{1}{4} $
B) $ \frac{1}{3} $
C) $ \frac{1}{2} $
D) $ \frac{2}{3} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ P(A)=P(A\cap B)+P(A\cup B)-P(B) $
$ =\frac{1}{3}+\frac{5}{6}-\frac{2}{3}=\frac{3}{6}=\frac{1}{2}. $
BETA
