$ P(A\cap B)=z, $ then $ P(\bar{A}\cap B) $ equals
[AMU 1999]
A) $ (1-x)y $
B) $ 1-x+y $
C) y ? z
D) $ 1-x+y-z $
Correct Answer: C
$ P(\bar{A}\cap B)=P(B)-P(A\cap B)=y-z. $
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