Probability Question 28
Question: A word consists of 11 letters in which there are 7 consonants and 4 vowels. If 2 letters are chosen at random, then the probability that all of them are consonants, is
Options:
A) $ \frac{5}{11} $
B) $ \frac{21}{55} $
C) $ \frac{4}{11} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Required probability $ =\frac{{}^{7}C_2}{{}^{11}C_2}=\frac{7.6}{11.10}=\frac{21}{55}. $
BETA
