Probability Question 29

Question: Assuming that for a husband-wife couple the chances of their child being a boy or a girl are the same, the probability of their two children being a boy and a girl is

[MP PET 1998]

Options:

A) $ \frac{1}{4} $

B) 1

C) $ \frac{1}{2} $

D) $ \frac{1}{8} $

Show Answer

Answer:

Correct Answer: C

Solution:

The chance of being a boy or girl $ p=\frac{1}{2}, $

$ q=\frac{1}{2} $ Total child = 2, Number of boys = 1 $ P $ (1 boys, 1 girl) $ ={}^{2}C_1{{( \frac{1}{2} )}^{1}}{{( \frac{1}{2} )}^{2-1}}=\frac{1}{2}. $