Probability Question 307
Question: A father has 3 children with at least one boy. The probability that he has 2 boys and 1 girl is
Options:
A) $ 1/4 $
B) $ 1/3 $
C) $ 2/3 $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Consider the following events:
A: Father has at least one boy
B: Father has 2 boys and one girl Then, A=one boy and 2 girls, 2 boys and one girl, 3 boys and no girl $ A\cap B=2 $ boys and one girl now, the required probability is $ P(A/B)=\frac{P(A\cap B)}{P(A)}=\frac{1}{3}. $
BETA
