Probability Question 31
Question: If Mohan has 3 tickets of a lottery containing 3 prizes and 9 blanks, then his chance of winning prize are
Options:
A) $ \frac{34}{55} $
B) $ \frac{21}{55} $
C) $ \frac{17}{55} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Mohan can gets one prize, 2 prizes or 3 prizes and his chance of failure means he get no prize.
Number of total ways $ ={}^{12}C_3=220 $
Favourable number of ways to be failure $ ={}^{9}C_3=84 $
Hence required probability $ =1-\frac{84}{220}=\frac{34}{55}. $
BETA
