Probability Question 329

Question: There are n letters and n addressed envelopes, the probability that all the letters are not kept in the right envelope, is

Options:

A) $ \frac{1}{n!} $

B) $ 1-\frac{1}{n!} $

C) $ 1-\frac{1}{n} $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Probability of all the letters kept in the right envelope is $ \frac{1}{n!} $ ( $ \because $ Total letters = n) i.e., $ P=\frac{1}{n!} $

We know, if q is the term used for the probability of the letters which are not kept in the right envelope.

Then $ p+q=1\Rightarrow q=1-p=1-\frac{1}{n!}. $



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