Probability Question 340
Question: If three vertices of a regular hexagon are chosen at random, then the chance that they form an equilateral triangle is:
Options:
A) $ \frac{1}{3} $
B) $ \frac{1}{5} $
C) $ \frac{1}{10} $
D) $ \frac{1}{2} $
Show Answer
Answer:
Correct Answer: C
Solution:
Three vertices can be selected in $ ^{6}C_3 $ ways. The only equilateral triangles possible are $ A_1A_3A_5 $ and $ A_2A_4A_6 $
$ p=\frac{2}{^{6}C_3}=\frac{2}{20}=\frac{1}{10} $
BETA
