Probability Question 346
Question: A coin is tossed three times. Consider the following events:
A: No head appears
B: Exactly one head appears
C: At least two heads appear
Which one of the following is correct?
Options:
A) $ (A\cup B)\cap (A\cup C)=B\cup C $
B) $ (A\cap B’)\cup (A\cap C’)=B’\cup C’ $
C) $ A\cap (B’\cup C’)=A\cup B\cup C $
D) $ A\cap (B’\cup C’)=B’\cap C’ $
Show Answer
Answer:
Correct Answer: D
Solution:
$ U={(HHH)(HHT)(HTH)(HTT) $
$ (THH)(THT)(TTH)(TTT)} $
$ A={(TTT)} $
$ B={(HTT)(THT)(TTH)} $
$ C={(HHH)(HHT)(HTH)(THH)} $
By checking the options $ (d)A\cap (B’\cup C’)=B’\cap C’ $ is correct.
BETA
