Probability Question 353

Question: If the papers of 4 students can be checked by any one of the 7 teachers, then the probability that all the 4 papers are checked by exactly 2 teachers is

Options:

A) 2/7

B) 12/49

C) 32/343

D) None of these

Show Answer

Answer:

Correct Answer: D

Solution:

The total number of ways in which papers of 4 students can be checked by seven teachers is $ 7^{4}. $

The number of ways of choosing two teachers out of 7 is $ ^{7}C_2. $ The number of ways in which they can check four papers is $ 2^{4}. $

But this includes two ways, in which all the papers will be checked by a single teacher.

Therefore, the number of ways in which 4 papers can be checked by exactly two teachers is $ 2^{4}-2=14. $

Therefore, the number of favourable ways is $ {{7}}C_2 \times 14 = (21)(14). $

Thus, the required probability is $ (21)(14)/7^{4}=6/49. $



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