Probability Question 36
Question: A committee of five is to be chosen from a group of 9 people. The probability that a certain married couple will either serve together or not at all, is
[CEE 1993]
Options:
A) $ \frac{1}{2} $
B) $ \frac{5}{9} $
C) $ \frac{4}{9} $
D) $ \frac{2}{9} $
Show Answer
Answer:
Correct Answer: C
Solution:
Required probability $ =\frac{{}^{7}C_3}{{}^{9}C_5}+\frac{{}^{7}C_5}{{}^{9}C_5}=\frac{56}{126}=\frac{4}{9}. $
BETA
