Probability Question 361
Question: An aircraft has three engines A, B, and C. The aircraft crashes if all the three engines fail. The probability of failure are $ 0.06,0.02 $ and $ 0.05 $ for engines A, B and C respectively. What is the probability that the aircraft will not crash-
Options:
A) $ 0.00003 $
B) $ 0.90 $
C) $ 0.99997 $
D) $ 0.90307 $
Show Answer
Answer:
Correct Answer: C
Solution:
Since, Probabilities of failure for engines A,B and C P(A), P[b] and P[c] are 0.03, 0.02 and 0.05 respectively. The aircraft will crash only when all the three engine fail. So, probability that it crashes $ =P(A).P(B).P(C) $
$ =0.03\times 0.02\times 0.05 $
$ =0.00003 $ Hence, the probability that the aircraft will not Crash $ =1-0.00003 $
$ =0.99997 $
BETA
