Probability Question 363
Question: The probability that the birth days of six different persons will fall in exactly two calendar months is
Options:
A) $ \frac{1}{6} $
B) $ ^{12}C_2\times \frac{2^{6}}{12^{6}} $
C) $ ^{12}C_2\times \frac{2^{6}-1}{12^{6}} $
D) $ \frac{341}{12^{5}} $
Show Answer
Answer:
Correct Answer: D
Solution:
Exhaustive number of cases $ =12^{6} $ Favourable cases $ {{=}^{12}}C_2(2^{6}-2) $
$ \therefore $ Probability $ =\frac{^{12}C_2(2^{6}-2)}{12^{6}}=\frac{341}{12^{5}} $
BETA
