Probability Question 386
Question: Two dice are thrown. What is the probability that the sum of the faces equals or exceeds 10?
Options:
A) 1/12
B) ¼
C) 1/3
D) 1/6
Show Answer
Answer:
Correct Answer: D
Solution:
Let E be the sum of the face equals or exceeds.
Then, $ E={(5,5),(4,6),(6,4),(5,6),(6,5),(6,6)} $
$ \therefore n(E)=6 $
Hence, $ P(E)=\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6} $
BETA
