Probability Question 401
Question: Seven people set themselves indiscriminately at round table. The probability that two distinguished person will be next to each is
Options:
A) $ \frac{1}{3} $
B) $ \frac{1}{2} $
C) $ \frac{1}{4} $
D) $ \frac{2}{3} $
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Answer:
Correct Answer: A
Solution:
Seven people can seat themselves at a round table in 6! Ways.
The number of ways in which two distinguished persons will be next to each other $ r=2(5)! $ .
Hence, the required probability $ =\frac{2(5)!}{6!}=\frac{1}{3}. $