Probability Question 409
Question: In a lottery there were 90 tickets numbered 1 to 90. Five tickets were drawn at random. The probability that two of the tickets drawn numbers 15 and 89 is
[AMU 2001]
Options:
A) $ \frac{2}{801} $
B) $ \frac{2}{623} $
C) $ \frac{1}{267} $
D) $ \frac{1}{623} $
Correct Answer: A
Show Answer
Answer:
Solution:
Required probability $ =\frac{^{88}C_3}{^{90}C_5}=\frac{2}{801} $ .
BETA
