Probability Question 41
Question: If $ P(A)=2/3 $ , $ P(B)=1/2 $ and $ P(A\cup B)=5/6 $ then events A and B are
[Kerala (Engg.) 2002]
Options:
A) Mutually exclusive
B) Independent as well as mutually exhaustive
C) Independent
D) Dependent only on A
Show Answer
Answer:
Correct Answer: A
Solution:
$ P(A\cup B)=P(A)+P(B)-P(A\cap B) $
$ \frac{5}{6}=\frac{2}{3}+\frac{1}{2}-P(A\cap B) $
$ \Rightarrow P(A\cap B)=0 $
Events A and B are mutually exclusive.
BETA
