Probability Question 410
Question: Among 15 players, 8 are batsmen and 7 are bowlers. Find the probability that a team is chosen of 6 batsmen and 5 bowlers
[UPSEAT 2002]
Options:
A) $ \frac{{}^{8}C_6\times {}^{7}C_5}{{}^{15}C_{11}} $
B) $ \frac{^{8}C_6{{+}^{7}}C_5}{^{15}C_{11}} $
C) $ \frac{15}{28} $
D) None of these
Correct Answer: A
Show Answer
Answer:
Solution:
Total number of ways $ ={{\,}^{15}}C_{11} $ Favourable cases $ ={{\,}^{8}}C_6 $ $ \times {{\,}^{7}}C_5 $ Required probability $ =\frac{^{8}C_6\times {{\,}^{7}}C_5}{^{15}C_{11}}. $
BETA
