Probability Question 416
Question: A bag contains 4 white, 5 red and 6 green balls. Three balls are picked up randomly. The probability that a white, a red and a green ball is drawn is
Options:
A) $ \frac{15}{91} $
B) $ \frac{30}{91} $
C) $ \frac{20}{91} $
D) $ \frac{24}{91} $
Correct Answer: D
Show Answer
Answer:
Solution:
Required probability $ =\frac{4\,.\,5\,.\,6}{{}^{15}C_3}=\frac{24}{91}. $
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