Probability Question 430
Question: Fifteen persons among whom are A and B, sit down at random at a round table. The probability that there are 4 persons between A and B, is
Options:
A) $ \frac{1}{3} $
B) $ \frac{2}{3} $
C) $ \frac{2}{7} $
D) $ \frac{1}{7} $
Correct Answer: D
Show Answer
Answer:
Solution:
Let $ A $ occupy any seat at the round table. Then there are 14 seats available for $ B. $ If there are to be four persons between $ A $ and $ B. $ Then $ B $ has only two ways to sit, as show in the fig. Hence required probability $ =\frac{2}{14}=\frac{1}{7}. $
BETA
