Probability Question 5
Question: Three numbers are chosen at random without replacement from the set $A=\{x \mid 1 \leq x \leq 10, x \in N\}$. The probability that the minimum of the chosen numbers is 3 and maximum is 7 , is
Options:
A) $ \frac{1}{12} $
B) $ \frac{1}{15} $
C) $\frac{11}{40}$
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ n(S){{=}^{10}}C_3 $ and $ n(E){{=}^{3}}C_1 $
becomes on selecting $ 3,7 $ and we have to select one from 4, 5 and 6.
$ \therefore P(E)=\frac{^{3}C_1}{^{10}C_3}=\frac{1}{40}. $
BETA
