Probability Question 57
Question: In an organization number of women are $ \mu $ times than that of men. If n things are distributed among them and the probability that the number of things Received by men are odd is $ \frac{1}{2}-{{( \frac{1}{2} )}^{n+1}} $ , then $ \mu $ equal to
Options:
A) 1
B) 2
C) 3
D) $ \frac{1}{4} $
Show Answer
Answer:
Correct Answer: C
Solution:
If p and q probabilities that a thing goes to a man and woman respectively, then $ p=\frac{1}{1+\mu },q=\frac{\mu }{1+\mu } $ Now, given probability $ {{=}^{n}}C_1{q^{n-1}}p{{+}^{n}}C_3{q^{n-3}}p^{3}{{+}^{n}}C_5{q^{n-1}}p^{5}+…. $
BETA
