Probability Question 77
Question: Six boys and six girls sit in a row randomly. The probability that the six girls sit together
Options:
A) $ \frac{1}{77} $
B) $ \frac{1}{132} $
C) $ \frac{1}{231} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
6 boys and 6 girls can be arranged in a row in $ 12! $ ways.
If all the 6 girls are together, then the number of arrangement are $ 7!\times 6! $ .
Hence required probability $ =\frac{7!.6!}{12!} $
$ =\frac{6\times 5\times 4\times 3\times 2}{12\times 11\times 10\times 9\times 8}=\frac{1}{132} $ .
BETA
