Probability Question 80

Question: A bag contains 4 white and 3 red balls. Two draws of one ball each are made without replacement. Then the probability that both the balls are red is

Options:

A) $ \frac{1}{7} $

B) $ \frac{2}{7} $

C) $ \frac{3}{7} $

D) $ \frac{4}{7} $

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Answer:

Correct Answer: A

Solution:

Required probability $ =\frac{{}^{3}C_1}{{}^{7}C_1}\times \frac{{}^{2}C_1}{{}^{6}C_1}=\frac{1}{7} $ .