Probability Question 83

Question: Out of 40 consecutive natural numbers, two are chosen at random. Probability that the sum of the numbers is odd, is

[MP PET 1997; Pb. CET 2000]

Options:

A) $ \frac{14}{29} $

B) $ \frac{20}{39} $

C) $ \frac{1}{2} $

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Required probability $ =\frac{{}^{20}C_1\times {}^{20}C_1}{{}^{40}C_2}=\frac{20\times 20\times 2}{40\times 39}=\frac{20}{39}. $