Probability Question 85
Question: Five coins whose faces are marked 2, 3 are tossed. The chance of obtaining a total of 12 is
[MP PET 2001; Pb. CET 2000]
Options:
A) $ \frac{1}{32} $
B) $ \frac{1}{16} $
C) $ \frac{3}{16} $
D) $ \frac{5}{16} $
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Answer:
Correct Answer: D
Solution:
Condition for sum of 12 is 2, 2, 2, 3, 3
$ \therefore $ Required probability $ ={{}^{5}}C_3{{( \frac{1}{2} )}^{3}}{{( \frac{1}{2} )}^{2}} $
$ =10.\frac{1}{2^{5}}=\frac{5}{16}. $
BETA
