Probability Question 91
Question: A bag contains 3 red, 4 white and 5 black balls. Three balls are drawn at random. The probability of being their different colours is
[RPET 1999]
Options:
A) $ \frac{3}{11} $
B) $ \frac{2}{11} $
C) $ \frac{8}{11} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
Probability $ =\frac{^{3}C_1{{.}^{4}}C_1{{.}^{5}}C_1}{^{12}C_3} $ $ =\frac{3}{11} $ .
BETA
