Relations And Functions Practice Questions Ques18
Question: If $f(x) = x^2$ and $g(x) = \sqrt{x}$, what is $(f \circ g)(16)$?
Options:
(A) 16
(B) 4
(C) 256
(D) 8
Show Answer
Answer: A
Explanation:
(A) Correct. $(f \circ g)(x) = f(g(x)) = f(\sqrt{x}) = (\sqrt{x})^2$. So, $(f \circ g)(16) = (\sqrt{16})^2 = 4^2 = 16$
(B) Incorrect. This is the result of $g(16)$, not $(f \circ g)(16)$
(C) Incorrect. This would be the result of $(g \circ f)(16)$, not $(f \circ g)(16)$
(D) Incorrect. This is not the correct composition of the functions
BETA
